Get SBS File Location

[rd.design]

Hello,

Apologies for the basic question, but I cannot for the life of me figure out how to get the SBS file location of the file I have open currently in SD2018.3 even after going through some of the API documentation

Code: [Select]

import sd
import sdplugins

from LTools.Tools import Exporter

class ExportToTGAFullSize(sdplugins.Plugin):
    sPluginDesc = sdplugins.PluginDesc(
        aLabel = 'Export To TGA - FullSize',
        aTooltip = 'Exports the TGAs of the current Substance Graph to the Data Folder',
        aPluginLocation = sdplugins.PluginLocationMenu(sdplugins.MenuId.Scripts, 'LTools', 0),
        aIconFileAbsPath = '')

    def run(self, aContext) :
#How to get the current file location so exporter knows where to mirror this in Project>Data?
        Exporter.Export(ArtSourceFileLocation, 100)
        pass

# Register module classes
sd.getContext().getSDApplication().registerModule(__name__)

Basically what I'm looking for is something like: pm.sceneName() in Pymel/Maya which returns a value like-
P:/LTP4/Projects/ArtSource/Environments/Props/Crate_Clean.mb

Something like this but, in SBS format.... So
P:/LTP4/Projects/ArtSource/Environments/Materials/Shared/Wood_Clean.sbs

I also apologies for it being SD2018.3, but it is what our studio is running currently and I do not believe we are upgrading to a newer version of SD just yet

TIA

[Cyrille Damez]

Please see this thread :
https://forum.substance3d.com/index.php/topic,33259.0.html

[rd.design]

Please see this thread :
https://forum.substance3d.com/index.php/topic,33259.0.html

Thank you for responding Cyrille, but in that post I'm unable to use ui_mgr as its something that was added to newer versions of SD and is not present on 2018.3. I'm looking for something like that ...

[rd.design]

Nevermind, the studio has agreed to upgrade Painter and Designer to 2020. Dear diary, today was a good day!